Dig straight down through the centre of the Earth from Cleveland, United States of America 🇺🇸, home to about 1.89 million people, and you would surface in Indian Ocean 🌊, at 41.4719° S, 98.3031° E. Like most of the planet, that spot is open ocean; only 66 of the 391 cities listed here have an antipode on land.
| City | Cleveland, United States of America 🇺🇸 |
|---|---|
| City coordinates | 41.4719° N, 81.6969° W |
| Antipode coordinates | 41.4719° S, 98.3031° E |
| What is there | Indian Ocean 🌊 (open water) |
| Nearest land | Australia 🇦🇺 — 1,668 km (1,036 miles) away |
| Nearest town or city | Busselton, Australia — 1,731 km (1,076 miles) away |
| Distance straight through the Earth | 12,742 km (7,918 miles) |
Cleveland's antipode is in open water, in Indian Ocean 🌊. The point lies roughly 1,668 km (1,036 miles) south-west of the nearest coast, which belongs to Australia 🇦🇺 — far enough out that no shore would be visible from it.
The closest settlement of any size is Busselton, Australia, about 1,731 km (1,076 miles) from the point.
63 other cities on this list surface in the same place as Cleveland; the 10 largest are shown.
Worked out by flipping the latitude across the equator (41.4719° N becomes 41.4719° S) and shifting the longitude by 180° (81.6969° W becomes 98.3031° E). More on how antipodes work.
New to it? How to play Antipodal.